`XY_(2)` dissociates as : `XY_(2(g)) hArr XY_((g)) + Y_((g))`. Initial pressure of `XY_(2)` is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of `K_(p)` is :

Options

A. 50
B. 100
C. 200
D. 400

Answer

B

Explanation

`{:(XY_(2(g)),hArr,XY_((g)),+,Y_((g))),(600-x,,x,,x):}`
600 + x = 800 or x = 200
Applying law of mass actin , `K_(p) = (200 xx 200)/(400) = 100`