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The half-life period of ""(53)I^(125) i...

The half-life period of `""_(53)I^(125)` is 60 days. What percent of radioactivity would be present after 240 days ?

Text Solution

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`t_(1//2) = 60` days, T = 240 days, `n = (T)/(t_(1//2)) = (240)/(60) = 4`
Radioactivity after 240 days ` = (N_(0))/(2^(4)) = (100)/(16) = 6.25%`
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