Home
Class 12
CHEMISTRY
Calculate the number of alpha and beta- ...

Calculate the number of `alpha` and `beta`- particles emitted in the disintegration of `""_(94)Pu^(241)` to `""_(83)Bi^(209)`.

Text Solution

Verified by Experts

Number of `alpha` - particles emitted ` = (a-y)/(4) = (241-209)/(4) = 8`
Number of `beta` - particles emitted ` = (x- b) + (a-y)/(2) = (83-94) + (241 - 209)/(2) = 5`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-I|45 Videos
  • NUCLEAR CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-II|38 Videos
  • NITROGEN COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Linked Comprehension Type)|9 Videos
  • P-BLOCK ELEMENTS

    BRILLIANT PUBLICATION|Exercise LEVEL-III|50 Videos

Similar Questions

Explore conceptually related problems

The total no. of alpha and beta - particles emitted in the nuclear reaction : ""_(92)^(238)U to ""_(82)^(214)Pb

Calculate number of alpha-and beta - particles emitted when ""_(92)^(238)U changes into radioactive ""_(82)^(206)Pb

Calculate the coulomb's force between two alpha particles separated by a distance of 3.2 xx 10^(-15)m .

In a radioactive series a nucleus X distintegrates into nucleus Y by emitting two alpha and two beta particles. IF m and n are the mass number and atomic number of the nucleus X, then the mass number and atomic number of the nucleus Y respectively are