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The total no. of alpha and beta- particl...

The total no. of `alpha` and `beta`- particles emitted in the nuclear reaction : `""_(92)^(238)U to ""_(82)^(214)Pb`

A

8

B

6

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(92)^(238)U to ""_(82)^(214)Pb + 6""_(2)^(4)He + 2""_(-1)^(0)e`
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Calculate number of alpha-and beta - particles emitted when ""_(92)^(238)U changes into radioactive ""_(82)^(206)Pb

Initially the earth was a fire-ball, slowly it has cooled to form earth crust and its different layers. At the beginning ""_(92)^(238)U was present and no ""_(82)^(206) Pb was there. With the passage of time, uranium decayed to ""_(82)^(206)Pb The decay process is : ""_(92)^(238)U underset((x alpha, y beta))to ""_(82)^(206)Pb , t_(1//2) of ""^(238)U = 4.5 xx 10^(9) yrs Atomic mass of ""^(238)U is 238.125 amu. Its packing fraction will be :

Initially the earth was a fire-ball, slowly it has cooled to form earth crust and its different layers. At the beginning ""_(92)^(238)U was present and no ""_(82)^(206) Pb was there. With the passage of time, uranium decayed to ""_(82)^(206)Pb The decay process is : ""_(92)^(238)U underset((x alpha, y beta))to ""_(82)^(206)Pb , t_(1//2) of ""^(238)U = 4.5 xx 10^(9) yrs x and y in above decay series are :

Initially the earth was a fire-ball, slowly it has cooled to form earth crust and its different layers. At the beginning ""_(92)^(238)U was present and no ""_(82)^(206) Pb was there. With the passage of time, uranium decayed to ""_(82)^(206)Pb The decay process is : ""_(92)^(238)U underset((x alpha, y beta))to ""_(82)^(206)Pb , t_(1//2) of ""^(238)U = 4.5 xx 10^(9) yrs A sample of rock from south America contains equal number of atoms of ""^(238)U and ""^(206)Pb . The age of the rock will be :

An heavier elements continuosly emits alpha - and beta -particles. The finally stable element may belong to :

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