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The element 'X' in the following reactio...

The element 'X' in the following reaction is : `""_(90)^(234)Th to 7_(2)^(4)He + 6""_(-1)^(0)e + X`

A

Pb

B

Sn

C

Tl

D

Hg

Text Solution

Verified by Experts

The correct Answer is:
A
The reaction is `""_(90)^(234)Th to 7""_(2)^(4)He + 6""_(-1)^(0)beta + ""_(z)^(A)X`
Now, 234 ` = 7(4) + 6(0) + A rArr A = 206and 90 = 7(2) + 6(-1) + Z` or Z = 82.
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