The observed massof `""_(26)^(56)Fe` is 55.9375 amu. Using the masses of proton and neutron as 1.00732 amu and 1.00866 amu respectively, calculate the binding energy per nucleon in joules

Options

A. `3.56 xx 10^(-12)` J
B. `2.06 xx 10^(-12)` J
C. `1.36 xx 10^(-12)` J
D. `4.14 xx 10^(-12)` J

Answer

C

Explanation

Mass of proton ` = 1.00732 xx 26 = 26.19032` amu, Mass of neutron ` 1.00866 xx 30 = 30.2598` amu
Total mass ` = 56.45012` amu, Mass defect `= 0.51262` amu
Binding energy ` =0.51262 xx 931.5 = 477.51` MeV
Binding energy per nucleon ` = (477.51)/(56) = 8.526 "MeV" = 8.526 xx 1.6 xx 10^(-13) J = 1.36 xx 10^(-12)` J