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The time required for a radioactive spec...

The time required for a radioactive species to decay `(2)/(3)` of its initial amount is 't'. The fraction of radioactive species left after t is :

A

`(1)/(sqrt(3))`

B

`(1)/(sqrt(5))`

C

`sqrt((2)/(3))`

D

`(1)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambdat = 2.303 log "" (1)/(1//3), lambda xx (1)/(2) t = 2.303 log "" (1)/(a) therefore 2 = (log3)/((log 1)/(a))`
`log "" (1)/(a) = (0.477)/(2) = 0.2385, " "(1)/(a) = 1.7318 " "therefore a = 0.5774 = (1)/(sqrt(3))`
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