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Hybridization, shape and magnetic moment...

Hybridization, shape and magnetic moment of `K_3[Co(CO)_3]` is

A

`d^2sp^3`, octahedral, 4.9 B.M.

B

`sp^3d^2`, octahedral, 4.9 B.M

C

`dsp^2`, square planar, 4.9 B.M.

D

`sp^3`, tetrahedral, 4.9 B.M.

Text Solution

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The correct Answer is:
B
In each case, magnetic moment is 4.9 B.M. which shows that each of them has 4 unpaired electrons. Further, in the given complex, oxidation state of cobalt is +3. Hence, it will have `3d^6` configuration, ie,

Thus, hybridisation possible is `sp^3d^2`,ie, outer orbital (high spin) octahedral complex.
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