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Cobalt(III) chloride forms several octah...

Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?

A

`CoCl_3 .5NH_3`

B

`CoCl_3 . 6NH_3`

C

`CoCl_3 . 3NH_3`

D

`CoCl_3 . 4 NH_3`

Text Solution

Verified by Experts

The correct Answer is:
C
As cabolt octahedral complexes for which coordiantion number = 6, the formulae of the given complexes will be
`[Co(NH_3)_5Cl]Cl_2, [Co(NH_3)_6]Cl_3 [ Co(NH_3)_3Cl_3] and [Co(NH_3)_4 Cl_2]Cl`
Thus, only (C ) does not have any ionizable chloride ion.
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