Amongst `Ni (CO)_4, [Ni(CN)_4]^(2-)` and `[NiCl_4]^(2-)`

Options

A. `Ni(CO)_4 and [NiCl_4]^(2-)` are dimagnetic and `[Ni(CN)_4]^(2-)` is paramagnetic
B. `[NiCl_4]^(2-) and [Ni(CN)_4]^(2-)` are diamagnetic and `Ni(CO)_4` is paramagnetic
C. `Ni(CO)_4 and [Ni(CN)_4]^(2-)` are diamgnetic and `[NiCl_4]^(2-)` is paramagnetic
D. `Ni(CO)_4 and [Ni(CN)_4]^(2-)` are diamagnetic and `[NiCl_4]^(2-)` is paramgnetic

Answer

C

Explanation

`[Ni(CO)_4] and [Ni(CN)_4]^(2-)` do not contain any unpaired electron while `[NiCl_4]^(2-)` contains two unpaired electrons.