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Amongst Ni (CO)4, [Ni(CN)4]^(2-) and [Ni...

Amongst `Ni (CO)_4, [Ni(CN)_4]^(2-)` and `[NiCl_4]^(2-)`

A

`Ni(CO)_4 and [NiCl_4]^(2-)` are dimagnetic and `[Ni(CN)_4]^(2-)` is paramagnetic

B

`[NiCl_4]^(2-) and [Ni(CN)_4]^(2-)` are diamagnetic and `Ni(CO)_4` is paramagnetic

C

`Ni(CO)_4 and [Ni(CN)_4]^(2-)` are diamgnetic and `[NiCl_4]^(2-)` is paramagnetic

D

`Ni(CO)_4 and [Ni(CN)_4]^(2-)` are diamagnetic and `[NiCl_4]^(2-)` is paramgnetic

Text Solution

Verified by Experts

The correct Answer is:
C
`[Ni(CO)_4] and [Ni(CN)_4]^(2-)` do not contain any unpaired electron while `[NiCl_4]^(2-)` contains two unpaired electrons.
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Explain how the complexes of Nickel. [Ni(CN)_4]^(2-) and [Ni (CO)_4 ] have different structure, but do not differ In their magnetic behaviour. (Ni, Atomic No : 28).

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Knowledge Check

  • Among [Ni (CO)_4], [Ni(CN)_4]^(2-), [NiCl_4]^(2-) species, the hybridisation states at the Ni atom are, respectively (Atomic number.of Ni=28)

    A
    `sp^3, dsp^2, dsp^2`
    B
    `sp^3, dsp^2, sp^3`
    C
    `sp^3, sp^3, dsp^2`
    D
    `dsp^2, sp^3, sp^3`

  • Among [Ni(CO)_4],[ Ni(CN)_4]^(2-), [NiCl_4]^(2-) species, the hybridisationstates at the Ni atom are, respectively (Atomic number of Ni = 28)

    A
    `sp^3, dsp^2, dsp^2`
    B
    `sp^3, dsp^2, sp^2`
    C
    `sp^3, sp^3,dsp^2`
    D
    `dsp^2, sp^3, sp^3`

  • Among [Ni(CO)_4], [NiCl_4]^(2-), [Co(NH_3)_4 Cl_2] Cl, Na_3 [CoF_6], Na_2O_2 and CsO_2 the total number of paramagnetic compounds is . : 2, 3, 4, 5

    A
    2
    B
    3
    C
    4
    D
    5

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