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The enthalpy of hydration of Cr^(2+) is ...

The enthalpy of hydration of `Cr^(2+)` is `-460 kcal mol^(-1)`. In the absence of CFSE, the value for `DeltaH = - 424 kcal mol^(-1)`. What is the value of `Delta_0` for `[Cr(H_2O)_6]^(2+)`

A

`60 " kcal mole"^(-1)`

B

`-60 " kcal mole"^(-1)`

C

`25.7" kcal mole"^(-1)`

D

`-25.7 " kcal mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Cr = 3d^5 4s^1, Cr^(2+) = 3d^(4).` Structure is `(t_(2g)^3 e_(g)^1)`.
CFSE = `(-0.4 xx 3 + 0.6) Delta_0 = -0.6 Delta_0`
`-0.6 Delta_0 = (-460) - (-24) = -36kcal mol^(-1)`
`Delta_0 = (-36)/(-0.6) = 60 k cal mol^(-1)`
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