Home
Class 12
CHEMISTRY
The number of geometrical isomers possib...

The number of geometrical isomers possible for the complex `[CoL_2Cl_2]^(-) (L = H_2NCH_2 CH_2O^(-))` is

Text Solution

Verified by Experts

The correct Answer is:
5

Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL III (Matching Column Type)|4 Videos
  • COORDINATION COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL III (Statement Type)|5 Videos
  • COORDINATION COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL III (Multiple Correct Answer Type)|12 Videos
  • CO-ORDINATION COMPOUNDS AND ORGANOMETALLICS

    BRILLIANT PUBLICATION|Exercise Level-II (Assertion- Reason)|4 Videos
  • D & F BLOCK ELEMENTS

    BRILLIANT PUBLICATION|Exercise Level -II|38 Videos

Similar Questions

Explore conceptually related problems

Total number of structural isomers possible for the C_(4)H_(10)O is

The total no. of isomers possible for the complex cation [CrCl_(2)(en)_(2)]^(+) is

The number of geometrical isomers in the following compound CH_3 -CH=CH-CH=CH-C_2H_5 is

The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH_3)(NH_2OH)]^(+) is (py = pyridine)

The number of possible isomers of an octạhedral complex [Co(C_2 O_4)_2,(NH_3)_2]^- : 1, 2, 3, 4

The total no.of isomers possible for the square planar complex [MBr_(2)Cl_(2)](SO)_(4) is ( SO_(4)^(2-) here acts as a bidentate ligand)

Number of possible isomers forthe complex [Co(en)_2 Cl_2]CI will be: (en=ethylenediamine)

The no.of geometrical isomers that can exist for the square planar complex [Pt(NH_(3))Cl(NH_(2)OH)(py)]^(+) is

How many position isomers are possible for CH_3-CH_2-CH_2-CH_2-CH_2-OH .