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A certain sum of money triple itself in ...

A certain sum of money triple itself in 8 years. In how many years it will be five times?

A

22 years

B

16 years

C

20 years

D

24 years

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concept of simple interest. ### Step 1: Understand the Problem We know that a certain sum of money triples itself in 8 years. We need to find out how many years it will take for the same sum to become five times. ### Step 2: Define Variables Let: - \( P \) = Principal amount (initial sum of money) - \( I \) = Interest earned - \( R \) = Rate of interest per annum - \( T \) = Time in years ### Step 3: Calculate Interest Earned in 8 Years If the money triples in 8 years, then: - After 8 years, the total amount \( A = 3P \) - The interest earned \( I \) can be calculated as: \[ I = A - P = 3P - P = 2P \] ### Step 4: Use the Simple Interest Formula The formula for simple interest is: \[ I = \frac{P \times R \times T}{100} \] Substituting the values we have: \[ 2P = \frac{P \times R \times 8}{100} \] ### Step 5: Simplify the Equation We can cancel \( P \) from both sides (assuming \( P \neq 0 \)): \[ 2 = \frac{R \times 8}{100} \] Now, multiply both sides by 100: \[ 200 = R \times 8 \] Now, divide by 8: \[ R = 25\% \] ### Step 6: Calculate Time for the Amount to Become Five Times Now we need to find out how long it will take for the amount to become five times: - Total amount when it becomes five times \( A = 5P \) - The interest earned in this case will be: \[ I = A - P = 5P - P = 4P \] ### Step 7: Set Up the Equation for Simple Interest Using the simple interest formula again: \[ 4P = \frac{P \times R \times T}{100} \] Substituting \( R = 25 \): \[ 4P = \frac{P \times 25 \times T}{100} \] ### Step 8: Simplify the Equation Again Cancel \( P \) from both sides: \[ 4 = \frac{25T}{100} \] Multiply both sides by 100: \[ 400 = 25T \] Now divide by 25: \[ T = 16 \] ### Conclusion It will take **16 years** for the sum of money to become five times. ---
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