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A man lends 10,000 in four parts. If he ...

A man lends 10,000 in four parts. If he gets 8% on `2000,7(1)/(2)%` on 4000 and `8(1)/(2)%` on 1400, what percent must he get for the remainder, if his average annual interest is 8.13% ?

A

`7%`

B

`9%`

C

`9(1)/(4)%`

D

`10(1)/(2)%`

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the total interest he should receive The man lends a total of ₹10,000 and wants an average annual interest of 8.13%. \[ \text{Total Interest} = \text{Principal} \times \text{Rate} = 10000 \times \frac{8.13}{100} = 813 \] ### Step 2: Calculate the interest from the first three parts 1. **Interest from ₹2000 at 8%:** \[ \text{Interest} = 2000 \times \frac{8}{100} = 160 \] 2. **Interest from ₹4000 at 7.5% (7(1)/(2)%):** \[ \text{Interest} = 4000 \times \frac{7.5}{100} = 300 \] 3. **Interest from ₹1400 at 8.5% (8(1)/(2)%):** \[ \text{Interest} = 1400 \times \frac{8.5}{100} = 119 \] ### Step 3: Calculate the total interest from the first three parts Now, we will sum the interests calculated above: \[ \text{Total Interest from first three parts} = 160 + 300 + 119 = 579 \] ### Step 4: Calculate the remaining interest needed To find out how much interest he still needs to earn to reach the total interest of ₹813: \[ \text{Remaining Interest} = 813 - 579 = 234 \] ### Step 5: Calculate the remaining principal The total principal lent is ₹10,000. The sum of the first three parts is: \[ \text{Sum of first three parts} = 2000 + 4000 + 1400 = 7400 \] Thus, the remaining principal is: \[ \text{Remaining Principal} = 10000 - 7400 = 2600 \] ### Step 6: Calculate the required interest rate for the remaining principal We need to find the interest rate \( r \) such that the interest from the remaining principal of ₹2600 gives us the remaining interest of ₹234. Using the formula for interest: \[ \text{Interest} = \text{Principal} \times \frac{Rate}{100} \] We can rearrange it to find the rate: \[ 234 = 2600 \times \frac{r}{100} \] Solving for \( r \): \[ r = \frac{234 \times 100}{2600} = \frac{23400}{2600} = 9 \] ### Final Answer The percentage he must get for the remainder is **9%**. ---
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