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A part of 38,800 is lent out at 6% per s...

A part of 38,800 is lent out at 6% per six months. The rest of the amount is lent out at 5% per annum after one year. The ratio of interest after 3 years from the time when first amount was lent out is 5 : 4. Find the second part that was lent out at 5%

A

26, 600

B

28800

C

27500

D

28000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Define the variables Let: - \( x \) = the amount lent out at 6% per six months - \( 38800 - x \) = the amount lent out at 5% per annum ### Step 2: Calculate the interest for each part 1. **Interest for the amount lent at 6% per six months**: - The interest rate for 6 months is 6%, which is equivalent to 12% per annum. - The amount is lent for 3 years, which is 6 periods of 6 months. - The formula for simple interest is: \[ \text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time} \] - Therefore, the interest for the first part is: \[ I_1 = x \times \frac{12}{100} \times 3 = x \times 0.36 \] 2. **Interest for the amount lent at 5% per annum**: - This amount is lent out after one year, so it will earn interest for 2 years. - The interest for this part is: \[ I_2 = (38800 - x) \times \frac{5}{100} \times 2 = (38800 - x) \times 0.1 \] ### Step 3: Set up the ratio of interests According to the problem, the ratio of the interest earned from the first part to the second part after 3 years is 5:4. Therefore, we can set up the equation: \[ \frac{I_1}{I_2} = \frac{5}{4} \] Substituting the expressions for \( I_1 \) and \( I_2 \): \[ \frac{x \times 0.36}{(38800 - x) \times 0.1} = \frac{5}{4} \] ### Step 4: Cross-multiply to solve for \( x \) Cross-multiplying gives: \[ 4 \times (x \times 0.36) = 5 \times ((38800 - x) \times 0.1) \] This simplifies to: \[ 1.44x = 1940 - 0.5x \] ### Step 5: Combine like terms Bringing all terms involving \( x \) to one side: \[ 1.44x + 0.5x = 1940 \] \[ 1.94x = 1940 \] ### Step 6: Solve for \( x \) Dividing both sides by 1.94: \[ x = \frac{1940}{1.94} \approx 1000 \] ### Step 7: Find the second part The second part lent out at 5% is: \[ 38800 - x = 38800 - 1000 = 37800 \] ### Final Answer The second part that was lent out at 5% per annum is **37,800**. ---
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DISHA PUBLICATION-INTEREST-Practice Exercises (Standard Level)
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  2. A man borrows 12,500 at 20% compound interest. At the end of every yea...

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  3. A part of 38,800 is lent out at 6% per six months. The rest of the amo...

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  13. Parmeshwarn invested an amount of Rs 12,000 at the rate of 10% per ann...

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  14. Simplify:- √400 + (5+2)^2 = ?

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  15. Two equal sums of money were invested, one at 4% and the other at 4.5%...

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  16. A sum of 725 is lent in the beginning of a year at a certain rate of ...

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  18. Simplify:- 192 * 4 = ?^2 - √256

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  19. A owes B 1,573, payable 1(1)/(2) years hence. Also B owes A 1,444.50,...

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  20. Seema invested an amount of 16,000 for two years on compound interest ...

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