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The population of towns A and B is the r...

The population of towns A and B is the ratio of 1 : 4. For the next 2 years, the population of A would increase and that of B would decrease by the same percentage every year. After 2 years, their population became equal. What is the percentage change in the population?

A

A)33.33

B

B)66.66

C

C)`25%`

D

D)Not possible

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The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Define the populations Let the population of town A be \( P_A \) and the population of town B be \( P_B \). According to the problem, the ratio of their populations is given as: \[ P_A : P_B = 1 : 4 \] This means we can express their populations as: \[ P_A = x \quad \text{and} \quad P_B = 4x \] where \( x \) is a common multiplier. ### Step 2: Define the percentage change Let the percentage change in population for both towns be \( x\% \). Therefore, the population of town A after 2 years will increase, while the population of town B will decrease. ### Step 3: Calculate the new populations After 2 years, the population of town A will be: \[ P_A' = P_A \times \left(1 + \frac{x}{100}\right)^2 = x \times \left(1 + \frac{x}{100}\right)^2 \] And the population of town B will be: \[ P_B' = P_B \times \left(1 - \frac{x}{100}\right)^2 = 4x \times \left(1 - \frac{x}{100}\right)^2 \] ### Step 4: Set the populations equal According to the problem, after 2 years, the populations of towns A and B become equal: \[ x \times \left(1 + \frac{x}{100}\right)^2 = 4x \times \left(1 - \frac{x}{100}\right)^2 \] We can cancel \( x \) from both sides (assuming \( x \neq 0 \)): \[ \left(1 + \frac{x}{100}\right)^2 = 4 \times \left(1 - \frac{x}{100}\right)^2 \] ### Step 5: Simplify the equation Taking the square root of both sides gives: \[ 1 + \frac{x}{100} = 2 \times \left(1 - \frac{x}{100}\right) \] Expanding the right side: \[ 1 + \frac{x}{100} = 2 - \frac{2x}{100} \] ### Step 6: Rearranging the equation Rearranging gives: \[ \frac{x}{100} + \frac{2x}{100} = 2 - 1 \] \[ \frac{3x}{100} = 1 \] Multiplying both sides by 100: \[ 3x = 100 \] Dividing by 3: \[ x = \frac{100}{3} \approx 33.33 \] ### Step 7: Conclusion The percentage change in the population is: \[ \text{Percentage change} = 33.33\% \]
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