Home
Class 14
MATHS
If the population of a town at the begin...

If the population of a town at the beginning of a year was 1530000, and the birth rate was 53.2, while the death rate was 31.2 per 1000 of the population, then the net increase in the population at the end of the year was

A

336600

B

363600

C

366300

D

330000

Text Solution

AI Generated Solution

The correct Answer is:
To find the net increase in the population of the town at the end of the year, we need to calculate the number of births and the number of deaths, and then find the difference between them. Here’s how to do it step by step: ### Step 1: Calculate the number of births The birth rate is given as 53.2 per 1000 of the population. 1. **Population at the beginning of the year**: 1,530,000 2. **Birth rate**: 53.2 per 1000 To find the number of births, we use the formula: \[ \text{Number of births} = \left(\frac{\text{Birth rate}}{1000}\right) \times \text{Population} \] Substituting the values: \[ \text{Number of births} = \left(\frac{53.2}{1000}\right) \times 1,530,000 \] Calculating this: \[ \text{Number of births} = 53.2 \times 1.53 = 81,636 \] ### Step 2: Calculate the number of deaths The death rate is given as 31.2 per 1000 of the population. 1. **Death rate**: 31.2 per 1000 Using the same formula: \[ \text{Number of deaths} = \left(\frac{\text{Death rate}}{1000}\right) \times \text{Population} \] Substituting the values: \[ \text{Number of deaths} = \left(\frac{31.2}{1000}\right) \times 1,530,000 \] Calculating this: \[ \text{Number of deaths} = 31.2 \times 1.53 = 47,796 \] ### Step 3: Calculate the net increase in population Now, we find the net increase by subtracting the number of deaths from the number of births: \[ \text{Net increase} = \text{Number of births} - \text{Number of deaths} \] Substituting the values: \[ \text{Net increase} = 81,636 - 47,796 \] Calculating this: \[ \text{Net increase} = 33,840 \] ### Final Answer The net increase in the population at the end of the year is **33,840**. ---
Promotional Banner

Topper's Solved these Questions

  • INTEREST

    DISHA PUBLICATION|Exercise Practice Exercises (Expert Level)|17 Videos
  • INTEREST

    DISHA PUBLICATION|Exercise Test Yourself|15 Videos
  • INTEREST

    DISHA PUBLICATION|Exercise Practice Exercises (Foundation Level)|27 Videos
  • INEQUALITIES

    DISHA PUBLICATION|Exercise Test Yourself|15 Videos
  • LINEAR EQUATIONS

    DISHA PUBLICATION|Exercise TEST YOUSELF|15 Videos

Similar Questions

Explore conceptually related problems

If the population P of a town increases at R% per annum, then its population after 5 years is …….

If in the population of a town there is an increase of 44% in the first year and 75% in the second year,then what is the average rate of increase in the population?

The population of a city was 20,000 in the year 1997. It increased at the rate of 5% p.a.Find the population at the end of the year 2000.

The population of a town was 110500. In one year it increased by 3608 due to new births. However, 8973 persons died or left the town during the year. What was the population at the end of the year?

The population of a town was 59000. In one year it was increased by 4536 due to new births.However,9218 persons died or left the town during the year.What was the population at the end of the year.

If the population of a town increased every year by 2.1% of the population at the beginning of that year,in how many years will the total increase of population be 20%

The population of a town increases at the rate of 10% per annum. If the present population of the town is 266200, then what was the population 3 years ago?

DISHA PUBLICATION-INTEREST-Practice Exercises (Standard Level)
  1. We had 1000 goats at the beginning of year 2001 and the no. of goats e...

    Text Solution

    |

  2. The population of towns A and B is the ratio of 1 : 4. For the next 2 ...

    Text Solution

    |

  3. If the population of a town at the beginning of a year was 1530000, an...

    Text Solution

    |

  4. Arun borrowed a sum of money from Jayant at the rate of 8% per annum s...

    Text Solution

    |

  5. What will be the difference between simple interest and compound inter...

    Text Solution

    |

  6. Aniket deposited two parts of a sum of 25000 in different banks at the...

    Text Solution

    |

  7. Mr. X invested an amount for 2 years at 15 percent per annum at simple...

    Text Solution

    |

  8. Mr Sridharan invested money in two schemes A and B, offering compound ...

    Text Solution

    |

  9. Parmeshwarn invested an amount of Rs 12,000 at the rate of 10% per ann...

    Text Solution

    |

  10. Simplify:- √400 + (5+2)^2 = ?

    Text Solution

    |

  11. Two equal sums of money were invested, one at 4% and the other at 4.5%...

    Text Solution

    |

  12. A sum of 725 is lent in the beginning of a year at a certain rate of ...

    Text Solution

    |

  13. David invested certain amount in three different schemes A, B and C wi...

    Text Solution

    |

  14. Simplify:- 192 * 4 = ?^2 - √256

    Text Solution

    |

  15. A owes B 1,573, payable 1(1)/(2) years hence. Also B owes A 1,444.50,...

    Text Solution

    |

  16. Seema invested an amount of 16,000 for two years on compound interest ...

    Text Solution

    |

  17. A finance company declares that, at a certain compound interest rate, ...

    Text Solution

    |

  18. Two friends A and B jointly lent out 81,600 at 4% per annum compound ...

    Text Solution

    |

  19. A money-lender, lends a part of his money at 10% per annum and the res...

    Text Solution

    |

  20. The simple interest on a sum of money is (1)/(9) th of the principal, ...

    Text Solution

    |