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A sum of 8000 is borrowed at 5% p.a. co...

A sum of 8000 is borrowed at 5% p.a. compound interest and paid back in 3 equal annual instalments. What is the amount of each instalment?

A

2937.67

B

3000

C

2037.67

D

2739.76

Text Solution

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The correct Answer is:
To solve the problem of finding the amount of each installment when a sum of 8000 is borrowed at 5% p.a. compound interest and paid back in 3 equal annual installments, we can follow these steps: ### Step 1: Define the Variables Let \( x \) be the amount of each installment. ### Step 2: Set Up the Equation Since the loan is paid back in 3 equal installments, we can express the total amount paid back in terms of \( x \): \[ 8000 = \frac{x}{(1 + \frac{5}{100})^1} + \frac{x}{(1 + \frac{5}{100})^2} + \frac{x}{(1 + \frac{5}{100})^3} \] ### Step 3: Simplify the Terms Calculate \( 1 + \frac{5}{100} \): \[ 1 + \frac{5}{100} = 1.05 \] Now, substitute this back into the equation: \[ 8000 = \frac{x}{1.05} + \frac{x}{(1.05)^2} + \frac{x}{(1.05)^3} \] ### Step 4: Calculate Each Term Calculate \( (1.05)^2 \) and \( (1.05)^3 \): \[ (1.05)^2 = 1.1025 \] \[ (1.05)^3 = 1.157625 \] Now substitute these values into the equation: \[ 8000 = \frac{x}{1.05} + \frac{x}{1.1025} + \frac{x}{1.157625} \] ### Step 5: Combine the Terms To combine the terms, find a common denominator, which is \( 1.05 \times 1.1025 \times 1.157625 \). However, we can also calculate the individual fractions: \[ \frac{x}{1.05} + \frac{x}{1.1025} + \frac{x}{1.157625} = x \left( \frac{1}{1.05} + \frac{1}{1.1025} + \frac{1}{1.157625} \right) \] ### Step 6: Calculate the Sum of the Fractions Calculate each fraction: \[ \frac{1}{1.05} \approx 0.95238 \] \[ \frac{1}{1.1025} \approx 0.90703 \] \[ \frac{1}{1.157625} \approx 0.86383 \] Now sum these values: \[ 0.95238 + 0.90703 + 0.86383 \approx 2.72324 \] ### Step 7: Substitute Back into the Equation Now substitute back into the equation: \[ 8000 = x \times 2.72324 \] ### Step 8: Solve for \( x \) To find \( x \): \[ x = \frac{8000}{2.72324} \approx 2937.67 \] ### Conclusion The amount of each installment is approximately: \[ \text{Each installment} \approx 2937.67 \]
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