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If log2=0.30103, find the number of digi...

If `log2=0.30103`, find the number of digits in `2^(56)`

A

A)17

B

B)31

C

C)100

D

D)200

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of digits in \( 2^{56} \), we can use the logarithmic property that relates the number of digits of a number \( n \) to its logarithm. The formula to find the number of digits \( d \) in a number \( n \) is given by: \[ d = \lfloor \log_{10} n \rfloor + 1 \] Here are the steps to solve the problem: ### Step 1: Define the number Let \( y = 2^{56} \). ### Step 2: Take the logarithm We need to find \( \log_{10} y \): \[ \log_{10} y = \log_{10} (2^{56}) \] ### Step 3: Use the power rule of logarithms Using the property of logarithms, we can rewrite this as: \[ \log_{10} (2^{56}) = 56 \cdot \log_{10} 2 \] ### Step 4: Substitute the value of \( \log_{10} 2 \) We know from the problem that \( \log_{10} 2 = 0.30103 \). Therefore: \[ \log_{10} (2^{56}) = 56 \cdot 0.30103 \] ### Step 5: Calculate the logarithm Now, we perform the multiplication: \[ 56 \cdot 0.30103 = 16.85668 \] ### Step 6: Find the number of digits Now, we apply the formula for the number of digits: \[ d = \lfloor 16.85668 \rfloor + 1 \] Calculating the floor function: \[ \lfloor 16.85668 \rfloor = 16 \] Thus, the number of digits is: \[ d = 16 + 1 = 17 \] ### Final Answer The number of digits in \( 2^{56} \) is **17**. ---
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