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If 7x + 3y + 9 = 0 and y = kx + 7 are tw...

If 7x + 3y + 9 = 0 and y = kx + 7 are two parallel lines then find the value of k.
(a)9/7
(b)-7/3
(c)5/8
(d)6/5

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The correct Answer is:
To solve the problem, we need to find the value of \( k \) such that the lines represented by the equations \( 7x + 3y + 9 = 0 \) and \( y = kx + 7 \) are parallel. ### Step-by-Step Solution: 1. **Identify the slope of the second line**: The second line is given in the slope-intercept form \( y = kx + 7 \). Here, the slope \( m_2 \) is simply \( k \). **Hint**: Remember that in the equation \( y = mx + c \), \( m \) represents the slope. 2. **Rearrange the first line to slope-intercept form**: We start with the equation \( 7x + 3y + 9 = 0 \). To convert this into the slope-intercept form \( y = mx + c \), we need to isolate \( y \): \[ 3y = -7x - 9 \] Now, divide everything by 3: \[ y = -\frac{7}{3}x - 3 \] Here, the slope \( m_1 \) of the first line is \( -\frac{7}{3} \). **Hint**: To find the slope, isolate \( y \) on one side of the equation. 3. **Set the slopes equal to each other**: Since the two lines are parallel, their slopes must be equal: \[ m_1 = m_2 \] Substituting the values we found: \[ -\frac{7}{3} = k \] **Hint**: For parallel lines, the slopes must be equal. 4. **Conclusion**: Therefore, the value of \( k \) is: \[ k = -\frac{7}{3} \] Thus, the correct answer is option (b) \( -\frac{7}{3} \).
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