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A (- 2, 4) and B (- 5, - 3) are two poin...

A (- 2, 4) and B (- 5, - 3) are two points. The coordinates of a point P on Y axis such that PA = PB, are
(a) (3, 4)
(b) (0, 9)
(c)(9, 0)
(d)(0, - 1)

A

(3, 4)

B

(0, 9)

C

(9, 0)

D

(0, - 1)

Text Solution

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The correct Answer is:
To find the coordinates of point P on the Y-axis such that the distances PA and PB are equal, we can follow these steps: ### Step 1: Understand the coordinates of points A and B - Point A has coordinates (-2, 4). - Point B has coordinates (-5, -3). - Point P is on the Y-axis, which means its coordinates can be represented as (0, y). ### Step 2: Use the distance formula The distance between two points (x1, y1) and (x2, y2) is given by the formula: \[ d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \] We need to find distances PA and PB. ### Step 3: Calculate distance PA Using point A (-2, 4) and point P (0, y): \[ PA = \sqrt{(0 - (-2))^2 + (y - 4)^2} = \sqrt{(2)^2 + (y - 4)^2} = \sqrt{4 + (y - 4)^2} \] ### Step 4: Calculate distance PB Using point B (-5, -3) and point P (0, y): \[ PB = \sqrt{(0 - (-5))^2 + (y - (-3))^2} = \sqrt{(5)^2 + (y + 3)^2} = \sqrt{25 + (y + 3)^2} \] ### Step 5: Set the distances equal Since PA = PB, we can set the two expressions equal to each other: \[ \sqrt{4 + (y - 4)^2} = \sqrt{25 + (y + 3)^2} \] ### Step 6: Square both sides to eliminate the square roots Squaring both sides gives: \[ 4 + (y - 4)^2 = 25 + (y + 3)^2 \] ### Step 7: Expand both sides Expanding the left side: \[ 4 + (y^2 - 8y + 16) = y^2 - 8y + 20 \] Expanding the right side: \[ 25 + (y^2 + 6y + 9) = y^2 + 6y + 34 \] ### Step 8: Set the expanded equations equal Now we have: \[ y^2 - 8y + 20 = y^2 + 6y + 34 \] ### Step 9: Simplify the equation Subtract \(y^2\) from both sides: \[ -8y + 20 = 6y + 34 \] Rearranging gives: \[ -8y - 6y = 34 - 20 \] \[ -14y = 14 \] ### Step 10: Solve for y Dividing both sides by -14: \[ y = -1 \] ### Step 11: Write the coordinates of point P Since point P is on the Y-axis, its coordinates are: \[ P(0, -1) \] ### Conclusion The coordinates of point P such that PA = PB are (0, -1), which corresponds to option (d). ---
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