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If (-1, -1) and (3, -1) are two opposite...

If (-1, -1) and (3, -1) are two opposite corners of a square, the other two corners a

A

(2, 0), (- 2, 2)

B

(2, -2), (0, 2)

C

(3,0), (4, - 2)

D

None of these

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The correct Answer is:
To find the other two corners of the square given the opposite corners (-1, -1) and (3, -1), we will follow these steps: ### Step 1: Identify the given points The two opposite corners of the square are: - Point A: (-1, -1) - Point B: (3, -1) ### Step 2: Find the midpoint of the diagonal The midpoint of the diagonal can be calculated using the midpoint formula: \[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] Substituting the coordinates of points A and B: \[ \text{Midpoint} = \left( \frac{-1 + 3}{2}, \frac{-1 + (-1)}{2} \right) = \left( \frac{2}{2}, \frac{-2}{2} \right) = (1, -1) \] ### Step 3: Determine the slope of the line segment AB The slope of the line segment connecting points A and B can be calculated as: \[ \text{Slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - (-1)}{3 - (-1)} = \frac{0}{4} = 0 \] This indicates that the line segment AB is horizontal. ### Step 4: Find the coordinates of the other two corners Since the square is oriented such that its sides are perpendicular to the line segment AB, the other two corners will be vertically aligned with the midpoint. The distance from the midpoint to each corner is equal to half the length of the diagonal. The length of the diagonal AB can be calculated as: \[ \text{Length of AB} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(3 - (-1))^2 + (-1 - (-1))^2} = \sqrt{(4)^2 + (0)^2} = 4 \] Thus, half the length of the diagonal is 2. ### Step 5: Calculate the coordinates of the other corners The other two corners will be located 2 units above and below the midpoint (1, -1): - Corner C: (1, -1 + 2) = (1, 1) - Corner D: (1, -1 - 2) = (1, -3) ### Final Answer The other two corners of the square are: - Corner C: (1, 1) - Corner D: (1, -3) ---
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