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The equation of a straight line which ma...

The equation of a straight line which makes an angle 45° with the x-axis with y-intercept 101 units is

A

10x + 101y = 1

B

101x + y = 1

C

x + y - 101 = 0

D

x - y + 101 = 0

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The correct Answer is:
To find the equation of a straight line that makes an angle of 45° with the x-axis and has a y-intercept of 101 units, we can follow these steps: ### Step 1: Understand the slope The slope (m) of a line that makes an angle θ with the x-axis is given by the formula: \[ m = \tan(\theta) \] For an angle of 45°, we have: \[ m = \tan(45°) = 1 \] ### Step 2: Identify the y-intercept The y-intercept (c) is the point where the line crosses the y-axis. According to the problem, the y-intercept is given as: \[ c = 101 \] ### Step 3: Write the equation of the line The general form of the equation of a straight line is: \[ y = mx + c \] Substituting the values of m and c into this equation, we get: \[ y = 1x + 101 \] or simply: \[ y = x + 101 \] ### Step 4: Rearranging the equation (optional) If we want to express the equation in standard form, we can rearrange it: \[ y - x - 101 = 0 \] This can also be written as: \[ -x + y - 101 = 0 \] ### Final Answer The equation of the straight line that makes an angle of 45° with the x-axis and has a y-intercept of 101 units is: \[ y = x + 101 \] or in standard form: \[ -x + y - 101 = 0 \] ---
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