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The number of words of four letters cont...

The number of words of four letters containing equal number of vowels and consonants, repetition being allowed, is

A

`105^2`

B

`210 xx 243`

C

`105 xx 243`

D

None of these

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The correct Answer is:
To find the number of four-letter words containing an equal number of vowels and consonants with repetition allowed, we can follow these steps: ### Step 1: Determine the Composition of the Word Since we need a four-letter word with an equal number of vowels and consonants, we will have: - 2 vowels - 2 consonants ### Step 2: Choose Positions for Vowels We need to select 2 positions out of 4 for the vowels. The number of ways to choose 2 positions from 4 is given by the combination formula \( \binom{n}{r} \): \[ \text{Ways to choose positions for vowels} = \binom{4}{2} \] ### Step 3: Calculate \( \binom{4}{2} \) Using the combination formula: \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] ### Step 4: Determine the Number of Vowels and Consonants Assuming we have: - 5 vowels (A, E, I, O, U) - 21 consonants (the remaining letters of the English alphabet) ### Step 5: Calculate the Number of Ways to Fill the Vowel and Consonant Positions Since repetition is allowed: - For each of the 2 vowel positions, we can choose any of the 5 vowels. - For each of the 2 consonant positions, we can choose any of the 21 consonants. Thus, the total number of ways to fill the vowel positions is: \[ \text{Ways to fill vowel positions} = 5 \times 5 = 25 \] And the total number of ways to fill the consonant positions is: \[ \text{Ways to fill consonant positions} = 21 \times 21 = 441 \] ### Step 6: Calculate the Total Number of Words Now, we can calculate the total number of four-letter words: \[ \text{Total words} = \text{Ways to choose positions for vowels} \times \text{Ways to fill vowel positions} \times \text{Ways to fill consonant positions} \] \[ \text{Total words} = 6 \times 25 \times 441 \] ### Step 7: Perform the Calculation Calculating this step-by-step: 1. \( 6 \times 25 = 150 \) 2. \( 150 \times 441 = 66150 \) Thus, the total number of four-letter words containing an equal number of vowels and consonants, with repetition allowed, is **66150**.
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