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A bouquet has to be formed from 18 diffe...

A bouquet has to be formed from 18 different flowers so that it should contain not less than three flowers. How many ways are there of doing this in?

A

5,24,288

B

2,62,144

C

2,61,972

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of forming a bouquet from 18 different flowers with the condition that it should contain at least 3 flowers, we can follow these steps: ### Step 1: Understand the Requirement We need to form a bouquet using at least 3 flowers from a total of 18 different flowers. This means we can choose 3, 4, 5, up to 18 flowers. ### Step 2: Use Combinations Since the order of flowers in the bouquet does not matter, we will use combinations. The number of ways to choose r flowers from n flowers is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] ### Step 3: Calculate the Total Combinations We need to calculate the combinations for choosing 3 to 18 flowers: \[ \text{Total Ways} = \binom{18}{3} + \binom{18}{4} + \binom{18}{5} + \ldots + \binom{18}{18} \] ### Step 4: Calculate Each Combination Now we will calculate each combination: 1. \(\binom{18}{3} = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816\) 2. \(\binom{18}{4} = \frac{18!}{4!(18-4)!} = \frac{18 \times 17 \times 16 \times 15}{4 \times 3 \times 2 \times 1} = 3060\) 3. \(\binom{18}{5} = \frac{18!}{5!(18-5)!} = \frac{18 \times 17 \times 16 \times 15 \times 14}{5 \times 4 \times 3 \times 2 \times 1} = 8568\) 4. \(\binom{18}{6} = 18564\) 5. \(\binom{18}{7} = 31824\) 6. \(\binom{18}{8} = 43758\) 7. \(\binom{18}{9} = 48620\) 8. \(\binom{18}{10} = 43758\) 9. \(\binom{18}{11} = 31824\) 10. \(\binom{18}{12} = 18564\) 11. \(\binom{18}{13} = 8568\) 12. \(\binom{18}{14} = 3060\) 13. \(\binom{18}{15} = 816\) 14. \(\binom{18}{16} = 153\) 15. \(\binom{18}{17} = 18\) 16. \(\binom{18}{18} = 1\) ### Step 5: Sum All Combinations Now we will sum all these values: \[ \text{Total Ways} = 816 + 3060 + 8568 + 18564 + 31824 + 43758 + 48620 + 43758 + 31824 + 18564 + 8568 + 3060 + 816 + 153 + 18 + 1 \] Calculating this gives us: \[ \text{Total Ways} = 261972 \] ### Final Answer Thus, the total number of ways to form the bouquet with at least 3 flowers from 18 different flowers is **261972**. ---
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