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If A=[{:(4i-6,10i),(14i,6+4i):}] and K=(...

If `A=[{:(4i-6,10i),(14i,6+4i):}] and K=(1)/(2i),` where `i= sqrt(-1)`. Then kA is equal to :

A

`[{:(2-3i,5),(7,2-3i):}]`

B

`[{:(2-3i,5),(7,5+3i):}]`

C

`[{:(2-3i,7),(5,3+3i):}]`

D

`[{:(2+3i,5),(7,2+3i):}]`

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