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Let A be a square matrix of order n xx n...

Let A be a square matrix of order `n xx n` where `n ge 2`. Let B be a matrix obtained from A with first and second rows interchanged. Then which one of the following is correct ?

A

A. det A = det B

B

B. det A = - det B

C

C. A = B

D

D. A = - B

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the determinants of matrix A and matrix B, where B is formed by interchanging the first and second rows of A. ### Step-by-Step Solution: 1. **Define the Matrix A**: Let matrix A be a 2x2 matrix represented as: \[ A = \begin{pmatrix} a & b \\ c & d \end{pmatrix} \] 2. **Calculate the Determinant of A**: The determinant of A (denoted as det(A)) is calculated as: \[ \text{det}(A) = ad - bc \] 3. **Form the Matrix B**: Matrix B is obtained by interchanging the first and second rows of matrix A: \[ B = \begin{pmatrix} c & d \\ a & b \end{pmatrix} \] 4. **Calculate the Determinant of B**: The determinant of B (denoted as det(B)) is calculated as: \[ \text{det}(B) = cb - da \] 5. **Relate the Determinants**: Notice that: \[ \text{det}(B) = cb - da = -(ad - bc) = -\text{det}(A) \] This shows that the determinant of B is the negative of the determinant of A. 6. **Conclusion**: Therefore, we conclude that: \[ \text{det}(A) = -\text{det}(B) \] This corresponds to option B from the given choices. ### Final Answer: The correct statement is: \[ \text{det}(A) = -\text{det}(B) \]
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