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What is the degree of the differential e...

What is the degree of the differential equation `[1 + ((dy)/(dx))^(2)]^(3//2) = k"" (d^(2) y)/(dx^(2)) ?`

A

4

B

3

C

2

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To find the degree of the given differential equation \[ \left[1 + \left(\frac{dy}{dx}\right)^{2}\right]^{\frac{3}{2}} = k \frac{d^{2}y}{dx^{2}}, \] we will follow these steps: ### Step 1: Identify the highest order derivative The highest order derivative in the equation is \(\frac{d^{2}y}{dx^{2}}\), which is the second derivative of \(y\). **Hint:** Look for the derivative with the highest order in the equation. ### Step 2: Rearrange the equation To analyze the degree, we can rearrange the equation. The left-hand side is raised to a power, so we can square both sides to eliminate the exponent. \[ 1 + \left(\frac{dy}{dx}\right)^{2} = \left(k \frac{d^{2}y}{dx^{2}}\right)^{\frac{2}{3}}. \] **Hint:** When dealing with powers, consider manipulating the equation to simplify the terms. ### Step 3: Simplify the equation Now, we can express the left-hand side without the exponent: \[ 1 + \left(\frac{dy}{dx}\right)^{2} = \frac{k^{2}}{3} \left(\frac{d^{2}y}{dx^{2}}\right)^{\frac{2}{3}}. \] **Hint:** Focus on isolating the highest order derivative to clearly see its power. ### Step 4: Determine the degree In the original equation, the highest order derivative is \(\frac{d^{2}y}{dx^{2}}\), and it appears to the power of 1 in the rearranged equation. The degree of a differential equation is defined as the power of the highest order derivative when the equation is a polynomial in derivatives. Since the highest order derivative \(\frac{d^{2}y}{dx^{2}}\) is raised to the power of 1, the degree of the differential equation is 2. **Hint:** The degree is determined by the highest power of the highest order derivative in the equation. ### Conclusion Thus, the degree of the differential equation is 2. **Final Answer:** The degree of the differential equation is 2 (Option C).
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PUNEET DOGRA-DIFFERENTIAL EQUATION -PREV YEAR QUESTIONS
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