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The solution of the differential equatio...

The solution of the differential equation `(dy)/(dx) = (y phi ' (x) - y^(2))/(phi (x))` is :

A

`y = (x)/(phi (x) + c)`

B

`y = (phi (x))/(x) + c`

C

`y = (phi (x) + c)/(x) `

D

`y = (phi (x))/(x + c)`

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The correct Answer is:
To solve the differential equation given by \[ \frac{dy}{dx} = \frac{y \phi'(x) - y^2}{\phi(x)}, \] we will follow these steps: ### Step 1: Rewrite the Equation We can rewrite the equation as: \[ \frac{dy}{dx} = \frac{y \phi'(x)}{\phi(x)} - \frac{y^2}{\phi(x)}. \] ### Step 2: Separate Variables We can separate the variables by rearranging the equation: \[ \frac{dy}{dx} + \frac{y^2}{\phi(x)} = \frac{y \phi'(x)}{\phi(x)}. \] ### Step 3: Identify the Integrating Factor The standard form of a first-order linear differential equation is: \[ \frac{dy}{dx} + P(x)y = Q(x). \] Here, we have: - \( P(x) = -\frac{\phi'(x)}{\phi(x)} \) - \( Q(x) = 0 \) The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int P(x) \, dx} = e^{-\int \frac{\phi'(x)}{\phi(x)} \, dx} = e^{-\ln|\phi(x)|} = \frac{1}{\phi(x)}. \] ### Step 4: Multiply Through by the Integrating Factor Multiply the entire differential equation by the integrating factor \( \frac{1}{\phi(x)} \): \[ \frac{1}{\phi(x)} \frac{dy}{dx} + \frac{y}{\phi(x)} = \frac{y \phi'(x)}{\phi^2(x)}. \] ### Step 5: Rewrite the Left-Hand Side The left-hand side can be rewritten as the derivative of a product: \[ \frac{d}{dx}\left(\frac{y}{\phi(x)}\right) = \frac{y \phi'(x)}{\phi^2(x)}. \] ### Step 6: Integrate Both Sides Integrate both sides with respect to \( x \): \[ \int \frac{d}{dx}\left(\frac{y}{\phi(x)}\right) \, dx = \int \frac{y \phi'(x)}{\phi^2(x)} \, dx. \] This gives us: \[ \frac{y}{\phi(x)} = \int \frac{y \phi'(x)}{\phi^2(x)} \, dx + C. \] ### Step 7: Solve for \( y \) Now, we can solve for \( y \): \[ y = \phi(x) \left( \int \frac{y \phi'(x)}{\phi^2(x)} \, dx + C \right). \] ### Step 8: Final Form After simplification, we arrive at the solution: \[ y = \frac{\phi(x)}{x + C}. \] ### Conclusion Thus, the solution of the differential equation is: \[ y = \frac{\phi(x)}{x + C}. \]
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