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What is the degree of the differential e...

What is the degree of the differential equation `(d^(2) y)/(dx^(2)) + 2 ((d^(2) y)/(dx^(2)))^(2) - (dy)/(dx) + y = 0`

A

6

B

3

C

2

D

1

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The correct Answer is:
To find the degree of the given differential equation \[ \frac{d^2 y}{dx^2} + 2 \left(\frac{d^2 y}{dx^2}\right)^2 - \frac{dy}{dx} + y = 0, \] we will follow these steps: ### Step 1: Identify the highest order derivative The highest order derivative in the equation is \(\frac{d^2 y}{dx^2}\), which is a second-order derivative. ### Step 2: Rewrite the equation in standard form The equation can be rewritten as: \[ \frac{d^2 y}{dx^2} + 2 \left(\frac{d^2 y}{dx^2}\right)^2 - \frac{dy}{dx} + y = 0. \] ### Step 3: Determine the polynomial form To find the degree, we need to express the equation as a polynomial in terms of the highest order derivative. Here, we can see that the term \(2 \left(\frac{d^2 y}{dx^2}\right)^2\) is a polynomial of degree 2 in \(\frac{d^2 y}{dx^2}\). ### Step 4: Identify the degree of the polynomial The degree of a differential equation is defined as the highest power of the highest order derivative when the equation is expressed as a polynomial. In this case, the highest order derivative is \(\frac{d^2 y}{dx^2}\) and it appears squared in the equation. ### Conclusion Thus, the degree of the given differential equation is **2**. ---
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