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What is the degree of the differential e...

What is the degree of the differential equation y = x ` (dy)/(dx) + ((dy)/(dx))^(-1)` ?

A

1

B

2

C

`-1`

D

Degree does not exist

Text Solution

AI Generated Solution

The correct Answer is:
To find the degree of the given differential equation \( y = x \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^{-1} \), we will follow these steps: ### Step 1: Identify the Differential Equation The given equation is: \[ y = x \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^{-1} \] ### Step 2: Multiply the Entire Equation by \(\frac{dy}{dx}\) To eliminate the inverse term, we multiply both sides of the equation by \(\frac{dy}{dx}\): \[ y \frac{dy}{dx} = x \left(\frac{dy}{dx}\right)^2 + 1 \] ### Step 3: Rearrange the Equation Rearranging the equation gives us: \[ x \left(\frac{dy}{dx}\right)^2 - y \frac{dy}{dx} + 1 = 0 \] ### Step 4: Identify the Highest Power of the Derivative In the rearranged equation, we can see that the highest power of \(\frac{dy}{dx}\) is 2 (it appears as \(\left(\frac{dy}{dx}\right)^2\)). ### Step 5: Determine the Degree of the Differential Equation The degree of a differential equation is defined as the power of the highest order derivative present in the equation. Since the highest power of \(\frac{dy}{dx}\) is 2, the degree of the differential equation is: \[ \text{Degree} = 2 \] Thus, the degree of the differential equation \( y = x \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^{-1} \) is 2. ### Final Answer The degree of the differential equation is 2. ---
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