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What is the equation of the curve passin...

What is the equation of the curve passing through the point ( 0 , `(pi)/(3)`) satisfying the differential equation sin x cos y dx + cos x sin y dy = 0 ?

A

`cos x cos y = (sqrt3)/(2)`

B

`sin x sin y = (sqrt3)/(2)`

C

`sin x sin y = (1)/(2)`

D

`cos x cos y = (1)/(2)`

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The correct Answer is:
To solve the given differential equation \( \sin x \cos y \, dx + \cos x \sin y \, dy = 0 \) and find the equation of the curve passing through the point \( (0, \frac{\pi}{3}) \), we will follow these steps: ### Step 1: Rearranging the Equation We start with the given differential equation: \[ \sin x \cos y \, dx + \cos x \sin y \, dy = 0 \] We can rearrange this to separate the variables: \[ \sin x \cos y \, dx = -\cos x \sin y \, dy \] Dividing both sides by \( \sin y \cos y \) (assuming \( \sin y \cos y \neq 0 \)): \[ \frac{\sin x}{\sin y} \, dx = -\frac{\cos x}{\cos y} \, dy \] ### Step 2: Separating Variables Now we can separate the variables: \[ \frac{\sin x}{\cos x} \, dx = -\frac{\sin y}{\cos y} \, dy \] This can be rewritten as: \[ \tan x \, dx = -\tan y \, dy \] ### Step 3: Integrating Both Sides Next, we integrate both sides: \[ \int \tan x \, dx = -\int \tan y \, dy \] The integral of \( \tan x \) is \( -\ln |\cos x| \), and similarly for \( y \): \[ -\ln |\cos x| = -(-\ln |\cos y|) + C \] This simplifies to: \[ \ln |\cos x| = \ln |\cos y| + C \] ### Step 4: Exponentiating Both Sides Exponentiating both sides gives: \[ |\cos x| = k |\cos y| \] where \( k = e^C \) is a constant. ### Step 5: Finding the Constant Using Initial Condition We need to find the value of \( k \) using the initial condition that the curve passes through the point \( (0, \frac{\pi}{3}) \): \[ |\cos(0)| = k |\cos(\frac{\pi}{3})| \] Calculating the cosine values: \[ 1 = k \cdot \frac{1}{2} \] Thus, we find: \[ k = 2 \] ### Step 6: Writing the Final Equation Substituting \( k \) back into the equation: \[ |\cos x| = 2 |\cos y| \] This can be simplified to: \[ \cos x = 2 \cos y \] This is the equation of the curve that satisfies the given differential equation and passes through the specified point. ### Final Answer The equation of the curve is: \[ \cos x = 2 \cos y \]
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