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If sec(7theta+28^(@))=cosec(30^(@)-3the...

If `sec(7theta+28^(@))=cosec(30^(@)-3theta)` then the value of `theta` is

A

`8^(@)`

B

`5^(@)`

C

`60^(@)`

D

`90^(@)`

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The correct Answer is:
To solve the equation \( \sec(7\theta + 28^\circ) = \csc(30^\circ - 3\theta) \), we can follow these steps: ### Step 1: Rewrite the cosecant function We know that \( \csc x = \sec(90^\circ - x) \). Therefore, we can rewrite the equation as: \[ \sec(7\theta + 28^\circ) = \sec(90^\circ - (30^\circ - 3\theta)) \] ### Step 2: Simplify the right side Now, simplify the right side: \[ 90^\circ - (30^\circ - 3\theta) = 90^\circ - 30^\circ + 3\theta = 60^\circ + 3\theta \] Thus, we have: \[ \sec(7\theta + 28^\circ) = \sec(60^\circ + 3\theta) \] ### Step 3: Set the angles equal Since the secant function is equal when the angles are equal (or differ by multiples of \(180^\circ\)), we can write: \[ 7\theta + 28^\circ = 60^\circ + 3\theta \] ### Step 4: Rearrange the equation Now, rearranging the equation gives: \[ 7\theta - 3\theta = 60^\circ - 28^\circ \] This simplifies to: \[ 4\theta = 32^\circ \] ### Step 5: Solve for \( \theta \) Now, divide both sides by 4: \[ \theta = \frac{32^\circ}{4} = 8^\circ \] ### Conclusion Thus, the value of \( \theta \) is: \[ \theta = 8^\circ \] ---
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KIRAN PUBLICATION-TRIGONOMETRY -TYPE - II
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