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If tan((pi)/(2)-(theta)/(2))=sqrt(3) , ...

If `tan((pi)/(2)-(theta)/(2))=sqrt(3)` , the value of `sectheta` is :

A

0

B

`(1)/(sqrt(2))`

C

`2`

D

1

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The correct Answer is:
To solve the problem, we start with the given equation: 1. **Given**: \[ \tan\left(\frac{\pi}{2} - \frac{\theta}{2}\right) = \sqrt{3} \] 2. **Using the co-function identity**: The tangent of an angle can be transformed using the co-function identity: \[ \tan\left(\frac{\pi}{2} - x\right) = \cot(x) \] Therefore, we can rewrite the equation as: \[ \cot\left(\frac{\theta}{2}\right) = \sqrt{3} \] 3. **Finding the angle**: The cotangent of an angle is equal to \(\sqrt{3}\) when the angle is: \[ \frac{\theta}{2} = \frac{\pi}{6} \quad \text{(since } \cot\left(\frac{\pi}{6}\right) = \sqrt{3}\text{)} \] 4. **Solving for \(\theta\)**: To find \(\theta\), we multiply both sides by 2: \[ \theta = 2 \times \frac{\pi}{6} = \frac{\pi}{3} \] 5. **Finding \(\sec(\theta)\)**: Now that we have \(\theta\), we can find \(\sec(\theta)\): \[ \sec(\theta) = \sec\left(\frac{\pi}{3}\right) \] The secant function is the reciprocal of the cosine function: \[ \sec\left(\frac{\pi}{3}\right) = \frac{1}{\cos\left(\frac{\pi}{3}\right)} \] We know that: \[ \cos\left(\frac{\pi}{3}\right) = \frac{1}{2} \] Therefore: \[ \sec\left(\frac{\pi}{3}\right) = \frac{1}{\frac{1}{2}} = 2 \] 6. **Final answer**: Thus, the value of \(\sec(\theta)\) is: \[ \sec(\theta) = 2 \]
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