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If tan alpha = n tan beta and sin alpha ...

If `tan alpha = n tan beta and sin alpha = m sin beta`, then `cos^2 alpha` is

A

`(m^(2))/(n^(2)+1)`

B

`(m^(2))/(n^(2))`

C

`(m^(2)-1)/(n^(2)-1)`

D

`(m^(2)+1)/(n^(2)+1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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