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Which one of the following is true f...

Which one of the following is true for `0^(@)ltthetalt90^(@)`?

A

`costhetalecos^(2)theta`

B

`costhetagtcos^(2)theta`

C

`costhetaltcos^(2)theta`

D

`costhetagecos^(2)theta`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the relationship between \(\cos \theta\) and \(\cos^2 \theta\) for \(0^\circ < \theta < 90^\circ\), we can follow these steps: ### Step 1: Understand the Functions We need to analyze the functions \(\cos \theta\) and \(\cos^2 \theta\). The cosine function decreases from 1 to 0 as \(\theta\) increases from \(0^\circ\) to \(90^\circ\). ### Step 2: Evaluate at Specific Angles Let's evaluate both \(\cos \theta\) and \(\cos^2 \theta\) at some key angles within the interval \(0^\circ < \theta < 90^\circ\): - For \(\theta = 0^\circ\): - \(\cos 0^\circ = 1\) - \(\cos^2 0^\circ = 1^2 = 1\) - For \(\theta = 30^\circ\): - \(\cos 30^\circ = \frac{\sqrt{3}}{2}\) - \(\cos^2 30^\circ = \left(\frac{\sqrt{3}}{2}\right)^2 = \frac{3}{4}\) - For \(\theta = 45^\circ\): - \(\cos 45^\circ = \frac{1}{\sqrt{2}} \approx 0.707\) - \(\cos^2 45^\circ = \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{1}{2}\) - For \(\theta = 60^\circ\): - \(\cos 60^\circ = \frac{1}{2}\) - \(\cos^2 60^\circ = \left(\frac{1}{2}\right)^2 = \frac{1}{4}\) ### Step 3: Compare Values Now, we compare the values of \(\cos \theta\) and \(\cos^2 \theta\) for each angle: - At \(0^\circ\): \(1 = 1\) - At \(30^\circ\): \(\frac{\sqrt{3}}{2} \approx 0.866 > \frac{3}{4} = 0.75\) - At \(45^\circ\): \(\frac{1}{\sqrt{2}} \approx 0.707 > \frac{1}{2} = 0.5\) - At \(60^\circ\): \(\frac{1}{2} = 0.5 > \frac{1}{4} = 0.25\) ### Step 4: General Conclusion From the evaluations, we can see that for \(0^\circ < \theta < 60^\circ\), \(\cos \theta > \cos^2 \theta\). At \(60^\circ\), they are equal, and for \(60^\circ < \theta < 90^\circ\), \(\cos \theta < \cos^2 \theta\). Thus, the relationship we are looking for is: \[ \cos \theta > \cos^2 \theta \text{ for } 0^\circ < \theta < 60^\circ \] ### Final Answer The true statement for \(0^\circ < \theta < 90^\circ\) is: \[ \cos \theta > \cos^2 \theta \text{ for } 0^\circ < \theta < 60^\circ \]
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