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If "cosec"theta+sintheta=(5)/(2) , then...

If `"cosec"theta+sintheta=(5)/(2)` , then the value of `("cosec"theta-sintheta)`is :

A

`-(3)/(2)`

B

`(3)/(2)`

C

`-(sqrt(3))/(2)`

D

`(sqrt(3))/(2)`

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The correct Answer is:
To solve the equation \( \csc \theta + \sin \theta = \frac{5}{2} \) and find the value of \( \csc \theta - \sin \theta \), we can follow these steps: ### Step 1: Rewrite the equation We know that \( \csc \theta = \frac{1}{\sin \theta} \). Therefore, we can rewrite the original equation as: \[ \frac{1}{\sin \theta} + \sin \theta = \frac{5}{2} \] ### Step 2: Multiply through by \( \sin \theta \) To eliminate the fraction, multiply every term by \( \sin \theta \): \[ 1 + \sin^2 \theta = \frac{5}{2} \sin \theta \] ### Step 3: Rearrange the equation Rearranging gives us: \[ \sin^2 \theta - \frac{5}{2} \sin \theta + 1 = 0 \] ### Step 4: Use the quadratic formula This is a quadratic equation in the form \( a\sin^2 \theta + b\sin \theta + c = 0 \). Here, \( a = 1 \), \( b = -\frac{5}{2} \), and \( c = 1 \). We can use the quadratic formula: \[ \sin \theta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Substituting the values: \[ \sin \theta = \frac{\frac{5}{2} \pm \sqrt{\left(-\frac{5}{2}\right)^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} \] \[ = \frac{\frac{5}{2} \pm \sqrt{\frac{25}{4} - 4}}{2} \] \[ = \frac{\frac{5}{2} \pm \sqrt{\frac{25}{4} - \frac{16}{4}}}{2} \] \[ = \frac{\frac{5}{2} \pm \sqrt{\frac{9}{4}}}{2} \] \[ = \frac{\frac{5}{2} \pm \frac{3}{2}}{2} \] ### Step 5: Calculate the two possible values for \( \sin \theta \) Calculating the two cases: 1. \( \sin \theta = \frac{5 + 3}{4} = \frac{8}{4} = 2 \) (not possible since \( \sin \theta \) cannot exceed 1) 2. \( \sin \theta = \frac{5 - 3}{4} = \frac{2}{4} = \frac{1}{2} \) ### Step 6: Find \( \csc \theta \) Now that we have \( \sin \theta = \frac{1}{2} \), we can find \( \csc \theta \): \[ \csc \theta = \frac{1}{\sin \theta} = \frac{1}{\frac{1}{2}} = 2 \] ### Step 7: Calculate \( \csc \theta - \sin \theta \) Now we can find \( \csc \theta - \sin \theta \): \[ \csc \theta - \sin \theta = 2 - \frac{1}{2} = \frac{4}{2} - \frac{1}{2} = \frac{3}{2} \] ### Final Answer Thus, the value of \( \csc \theta - \sin \theta \) is: \[ \frac{3}{2} \]
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