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(2sintheta)/(costheta(1+tan^(2)theta)) ...

`(2sintheta)/(costheta(1+tan^(2)theta))` simplifies to :

A

`costheta`

B

`cos2theta`

C

`sin2 theta`

D

`sintheta`

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AI Generated Solution

The correct Answer is:
To simplify the expression \(\frac{2 \sin \theta}{\cos \theta (1 + \tan^2 \theta)}\), we can follow these steps: ### Step 1: Rewrite the expression Start with the given expression: \[ \frac{2 \sin \theta}{\cos \theta (1 + \tan^2 \theta)} \] ### Step 2: Use the identity for \(1 + \tan^2 \theta\) Recall the trigonometric identity: \[ 1 + \tan^2 \theta = \sec^2 \theta \] Thus, we can rewrite the expression as: \[ \frac{2 \sin \theta}{\cos \theta \sec^2 \theta} \] ### Step 3: Rewrite \(\sec^2 \theta\) Since \(\sec \theta = \frac{1}{\cos \theta}\), we have: \[ \sec^2 \theta = \frac{1}{\cos^2 \theta} \] Substituting this into our expression gives: \[ \frac{2 \sin \theta}{\cos \theta \cdot \frac{1}{\cos^2 \theta}} = \frac{2 \sin \theta \cdot \cos^2 \theta}{\cos \theta} \] ### Step 4: Simplify the expression Now, simplify the expression: \[ \frac{2 \sin \theta \cdot \cos^2 \theta}{\cos \theta} = 2 \sin \theta \cdot \cos \theta \] ### Step 5: Use the double angle identity Recall the double angle identity: \[ \sin 2\theta = 2 \sin \theta \cos \theta \] Thus, we can write: \[ 2 \sin \theta \cos \theta = \sin 2\theta \] ### Final Result Therefore, the simplified form of the expression \(\frac{2 \sin \theta}{\cos \theta (1 + \tan^2 \theta)}\) is: \[ \sin 2\theta \] ---
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KIRAN PUBLICATION-TRIGONOMETRY -TYPE - II
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