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If sintheta+cosectheta=2, the value of...

If `sintheta+cosectheta=2`, the value of `sin^(100)theta+cosec^(100)theta` is :

A

1

B

2

C

3

D

4

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The correct Answer is:
To solve the problem, we need to find the value of \( \sin^{100} \theta + \csc^{100} \theta \) given that \( \sin \theta + \csc \theta = 2 \). ### Step-by-Step Solution: 1. **Start with the given equation:** \[ \sin \theta + \csc \theta = 2 \] 2. **Rewrite \( \csc \theta \) in terms of \( \sin \theta \):** \[ \csc \theta = \frac{1}{\sin \theta} \] So, we can rewrite the equation as: \[ \sin \theta + \frac{1}{\sin \theta} = 2 \] 3. **Multiply both sides by \( \sin \theta \) to eliminate the fraction:** \[ \sin^2 \theta + 1 = 2 \sin \theta \] 4. **Rearranging the equation gives:** \[ \sin^2 \theta - 2 \sin \theta + 1 = 0 \] 5. **Recognize this as a perfect square:** \[ (\sin \theta - 1)^2 = 0 \] 6. **Solve for \( \sin \theta \):** \[ \sin \theta - 1 = 0 \implies \sin \theta = 1 \] 7. **Determine the angle \( \theta \):** The value of \( \theta \) for which \( \sin \theta = 1 \) is: \[ \theta = 90^\circ \] 8. **Now find \( \sin^{100} \theta + \csc^{100} \theta \):** Since \( \sin 90^\circ = 1 \): \[ \sin^{100} 90^\circ = 1^{100} = 1 \] And since \( \csc 90^\circ = 1 \): \[ \csc^{100} 90^\circ = 1^{100} = 1 \] 9. **Combine the results:** \[ \sin^{100} \theta + \csc^{100} \theta = 1 + 1 = 2 \] ### Final Answer: \[ \sin^{100} \theta + \csc^{100} \theta = 2 \]
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