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The value of (sintheta)/(1+costheta)+(...

The value of `(sintheta)/(1+costheta)+(sintheta)/(1-costheta)` is :

A

`2sintheta`

B

`2costheta`

C

`2sectheta`

D

`2cosectheta`

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The correct Answer is:
To solve the expression \(\frac{\sin \theta}{1 + \cos \theta} + \frac{\sin \theta}{1 - \cos \theta}\), we can follow these steps: ### Step 1: Write the expression We start with the expression: \[ \frac{\sin \theta}{1 + \cos \theta} + \frac{\sin \theta}{1 - \cos \theta} \] ### Step 2: Find a common denominator The common denominator for the two fractions is \((1 + \cos \theta)(1 - \cos \theta)\). Thus, we can rewrite the expression as: \[ \frac{\sin \theta (1 - \cos \theta) + \sin \theta (1 + \cos \theta)}{(1 + \cos \theta)(1 - \cos \theta)} \] ### Step 3: Simplify the numerator Now, simplify the numerator: \[ \sin \theta (1 - \cos \theta) + \sin \theta (1 + \cos \theta) = \sin \theta - \sin \theta \cos \theta + \sin \theta + \sin \theta \cos \theta \] Combining like terms: \[ = \sin \theta + \sin \theta = 2\sin \theta \] ### Step 4: Simplify the denominator The denominator can be simplified using the difference of squares: \[ (1 + \cos \theta)(1 - \cos \theta) = 1 - \cos^2 \theta = \sin^2 \theta \] ### Step 5: Combine the results Now we can combine the simplified numerator and denominator: \[ \frac{2 \sin \theta}{\sin^2 \theta} \] ### Step 6: Simplify the fraction This simplifies to: \[ \frac{2}{\sin \theta} = 2 \csc \theta \] ### Step 7: Use the identity Since \(\csc \theta = \frac{1}{\sin \theta}\), we can also express this in terms of cosine: \[ = 2 \cdot \frac{1}{\sin \theta} = 2 \cdot \frac{\cos \theta}{\sin \theta \cdot \cos \theta} = 2 \cos \theta \] ### Final Result Thus, the value of the expression is: \[ \boxed{2 \cos \theta} \]
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