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If a sin45^(@).cos45^(@).tan60^(@)=tan^...

If a `sin45^(@).cos45^(@).tan60^(@)=tan^(2)45^(@)-cos60^(@)`, then find the value of a .

A

`(1)/(sqrt(3))`

B

`sqrt(3)`

C

1

D

`(sqrt(3))/(2)`

Text Solution

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The correct Answer is:
To solve the equation \( a \sin 45^\circ \cos 45^\circ \tan 60^\circ = \tan^2 45^\circ - \cos^2 60^\circ \), we will follow these steps: ### Step 1: Substitute the known values of trigonometric functions We know: - \( \sin 45^\circ = \frac{1}{\sqrt{2}} \) - \( \cos 45^\circ = \frac{1}{\sqrt{2}} \) - \( \tan 60^\circ = \sqrt{3} \) - \( \tan 45^\circ = 1 \) - \( \cos 60^\circ = \frac{1}{2} \) Substituting these values into the equation gives: \[ a \left(\frac{1}{\sqrt{2}}\right) \left(\frac{1}{\sqrt{2}}\right) \left(\sqrt{3}\right) = 1^2 - \left(\frac{1}{2}\right) \] ### Step 2: Simplify the left side of the equation The left side simplifies as follows: \[ a \left(\frac{1}{\sqrt{2}} \cdot \frac{1}{\sqrt{2}} \cdot \sqrt{3}\right) = a \left(\frac{1}{2} \cdot \sqrt{3}\right) = \frac{a \sqrt{3}}{2} \] ### Step 3: Simplify the right side of the equation The right side simplifies as follows: \[ 1 - \frac{1}{2} = \frac{1}{2} \] ### Step 4: Set the left side equal to the right side Now we have: \[ \frac{a \sqrt{3}}{2} = \frac{1}{2} \] ### Step 5: Solve for \( a \) To isolate \( a \), we multiply both sides by 2: \[ a \sqrt{3} = 1 \] Now, divide both sides by \( \sqrt{3} \): \[ a = \frac{1}{\sqrt{3}} \] ### Final Answer Thus, the value of \( a \) is: \[ \boxed{\frac{1}{\sqrt{3}}} \]
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