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If (1)/(costheta+sectheta)=(1)/(2) , wh...

If `(1)/(costheta+sectheta)=(1)/(2)` , what is the value of `cos^(100)theta+sec^(100)theta`?

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To solve the equation \(\frac{1}{\cos \theta + \sec \theta} = \frac{1}{2}\), we can follow these steps: ### Step 1: Cross-multiply the equation Starting with the given equation: \[ \frac{1}{\cos \theta + \sec \theta} = \frac{1}{2} \] Cross-multiplying gives: \[ 1 = \frac{1}{2}(\cos \theta + \sec \theta) \] ### Step 2: Multiply both sides by 2 Multiplying both sides by 2, we have: \[ 2 = \cos \theta + \sec \theta \] ### Step 3: Substitute \(\sec \theta\) with \(\frac{1}{\cos \theta}\) Recall that \(\sec \theta = \frac{1}{\cos \theta}\). Substituting this into the equation gives: \[ 2 = \cos \theta + \frac{1}{\cos \theta} \] ### Step 4: Let \(x = \cos \theta\) Let \(x = \cos \theta\). Then the equation becomes: \[ 2 = x + \frac{1}{x} \] ### Step 5: Multiply through by \(x\) To eliminate the fraction, multiply through by \(x\): \[ 2x = x^2 + 1 \] ### Step 6: Rearrange the equation Rearranging gives us: \[ x^2 - 2x + 1 = 0 \] ### Step 7: Factor the quadratic This can be factored as: \[ (x - 1)^2 = 0 \] ### Step 8: Solve for \(x\) Thus, we find: \[ x - 1 = 0 \implies x = 1 \] Since \(x = \cos \theta\), we have: \[ \cos \theta = 1 \] ### Step 9: Find \(\sec \theta\) Now, since \(\sec \theta = \frac{1}{\cos \theta}\): \[ \sec \theta = \frac{1}{1} = 1 \] ### Step 10: Calculate \(\cos^{100} \theta + \sec^{100} \theta\) Now we can calculate: \[ \cos^{100} \theta + \sec^{100} \theta = 1^{100} + 1^{100} = 1 + 1 = 2 \] ### Final Answer Thus, the value of \(\cos^{100} \theta + \sec^{100} \theta\) is: \[ \boxed{2} \]
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