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What is the value of ([tan(90-theta)+s...

What is the value of `([tan(90-theta)+sec(90-theta)-1])/([tan(90-theta)-sec(90-theta)+1])`?

A

`[1+costheta]/sintheta`

B

`[1+sintheta]/costheta`

C

`sintheta`

D

`costheta`

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The correct Answer is:
To solve the expression \(\frac{\tan(90^\circ - \theta) + \sec(90^\circ - \theta) - 1}{\tan(90^\circ - \theta) - \sec(90^\circ - \theta) + 1}\), we will use the trigonometric identities for \(\tan\) and \(\sec\). ### Step-by-step Solution: 1. **Use Trigonometric Identities**: We know that: \[ \tan(90^\circ - \theta) = \cot(\theta) \] \[ \sec(90^\circ - \theta) = \csc(\theta) \] Therefore, we can rewrite the expression as: \[ \frac{\cot(\theta) + \csc(\theta) - 1}{\cot(\theta) - \csc(\theta) + 1} \] 2. **Substituting the Identities**: Substitute the identities into the expression: \[ \frac{\cot(\theta) + \csc(\theta) - 1}{\cot(\theta) - \csc(\theta) + 1} \] 3. **Combine Terms**: Let's denote \(x = \cot(\theta)\) and \(y = \csc(\theta)\). The expression simplifies to: \[ \frac{x + y - 1}{x - y + 1} \] 4. **Simplifying the Expression**: Now we will simplify the expression: - The numerator is \(x + y - 1\). - The denominator is \(x - y + 1\). 5. **Factorizing**: We can factor or rearrange the terms if necessary, but in this case, we will directly evaluate the expression: \[ \frac{x + y - 1}{x - y + 1} \] 6. **Finding a Common Value**: To find a common value, we can analyze specific values of \(\theta\). For example, if we take \(\theta = 45^\circ\): - \(\cot(45^\circ) = 1\) - \(\csc(45^\circ) = \sqrt{2}\) Substituting these values gives: \[ \frac{1 + \sqrt{2} - 1}{1 - \sqrt{2} + 1} = \frac{\sqrt{2}}{2 - \sqrt{2}} \] 7. **Final Evaluation**: To simplify further, we can multiply the numerator and denominator by the conjugate of the denominator: \[ \frac{\sqrt{2}(2 + \sqrt{2})}{(2 - \sqrt{2})(2 + \sqrt{2})} = \frac{2\sqrt{2} + 2}{4 - 2} = \frac{2\sqrt{2} + 2}{2} = \sqrt{2} + 1 \] ### Conclusion: The value of the expression \(\frac{\tan(90^\circ - \theta) + \sec(90^\circ - \theta) - 1}{\tan(90^\circ - \theta) - \sec(90^\circ - \theta) + 1}\) simplifies to \(\sqrt{2} + 1\).
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