How many tiles, each 4 decimetre square, will be required to cover the floor of a room 8m long and 6m broad ?

Options

A. 200
B. 260
C. 280
D. 300

Answer

To solve the problem of how many tiles, each 4 decimetre square, will be required to cover the floor of a room that is 8 meters long and 6 meters broad, we can follow these steps:

### Step 1: Convert the dimensions of the room from meters to decimeters.
1 meter = 10 decimeters.
So,
- Length of the room = 8 m = 8 × 10 = 80 decimeters
- Breadth of the room = 6 m = 6 × 10 = 60 decimeters

### Step 2: Calculate the area of the floor of the room.
Area of the room = Length × Breadth
= 80 decimeters × 60 decimeters
= 4800 square decimeters

### Step 3: Calculate the area of one tile.
Area of one tile = 4 square decimeters (as given)

### Step 4: Calculate the number of tiles required.
Number of tiles required = Area of the room / Area of one tile
= 4800 square decimeters / 4 square decimeters
= 1200 tiles

### Final Answer:
Therefore, the number of tiles required to cover the floor of the room is **1200 tiles**.

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