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The outer circumference of a circular ra...

The outer circumference of a circular race-track is 528 metre. The track is everywhere 14 metre wide. Cost of levelling the track at the rate of Rs. 10 per sq. metre is :

A

Rs. 77660

B

Rs. 66760

C

Rs. 76760

D

Rs. 67760

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The correct Answer is:
To solve the problem step by step, we need to find the cost of levelling the circular race-track given its outer circumference and width. ### Step 1: Find the radius of the outer circle We know the outer circumference \( C \) of the circular race-track is given by the formula: \[ C = 2\pi R \] where \( R \) is the radius of the outer circle. Given: \[ C = 528 \text{ metres} \] Substituting the value of \( C \): \[ 528 = 2 \times \frac{22}{7} \times R \] ### Step 2: Solve for \( R \) To find \( R \), rearranging the equation gives: \[ R = \frac{528 \times 7}{2 \times 22} \] Calculating the right-hand side: \[ R = \frac{528 \times 7}{44} = \frac{3696}{44} = 84 \text{ metres} \] ### Step 3: Find the radius of the inner circle The width of the track is given as 14 metres. Therefore, the radius of the inner circle \( r \) is: \[ r = R - \text{width} = 84 - 14 = 70 \text{ metres} \] ### Step 4: Calculate the area of the track The area of the track is the difference between the area of the outer circle and the inner circle. The area \( A \) of a circle is given by: \[ A = \pi R^2 \] Calculating the area of the outer circle: \[ A_{\text{outer}} = \pi R^2 = \frac{22}{7} \times (84)^2 \] Calculating \( (84)^2 \): \[ (84)^2 = 7056 \] Thus, \[ A_{\text{outer}} = \frac{22}{7} \times 7056 = 22 \times 1008 = 22176 \text{ sq. metres} \] Calculating the area of the inner circle: \[ A_{\text{inner}} = \pi r^2 = \frac{22}{7} \times (70)^2 \] Calculating \( (70)^2 \): \[ (70)^2 = 4900 \] Thus, \[ A_{\text{inner}} = \frac{22}{7} \times 4900 = 22 \times 700 = 15400 \text{ sq. metres} \] ### Step 5: Calculate the area of the track Now, the area of the track \( A_{\text{track}} \) is: \[ A_{\text{track}} = A_{\text{outer}} - A_{\text{inner}} = 22176 - 15400 = 6786 \text{ sq. metres} \] ### Step 6: Calculate the cost of levelling the track The cost of levelling the track is given by: \[ \text{Cost} = \text{Area} \times \text{Rate} \] where the rate is Rs. 10 per sq. metre. Thus, \[ \text{Cost} = 6786 \times 10 = 67860 \text{ Rs.} \] ### Final Answer The cost of levelling the track is Rs. 67860. ---
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The outer circumference of a circular race-track is 528 m. The track is everywhere 14 m wide. Calculate the cost of levelling the track at the rate of 50 paise per square metre (U s e\ \ pi=22//7) .

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The inner and the outer radii of a circular track are 7 m and 14 m, respectively. Find the cost of levelling the track at the rate of rs. 100 per m^(2) . The following steps are involved in solving the above problem. Arrange them is sequential order (A) Area of circular track =pi(R^(2)-r^(2)) and given R = 14 m and r = 7 m (B) therefore "Area of circular track"=(22)/(7)(196-49) "(C) Area of the track "=(22)/(7)xx147=22xx21=154cm^(2) (D) "Cost of levelling the path "=462xx100="Rs."46,200

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