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Each side of a sqaure is increased by 10...

Each side of a sqaure is increased by 10%. The percentage increase in its area is :

A

25

B

12.5

C

20

D

21

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The correct Answer is:
To solve the problem of finding the percentage increase in the area of a square when each side is increased by 10%, follow these steps: ### Step 1: Understand the original area of the square Let the original side length of the square be \( a \). The area \( A \) of the square is given by the formula: \[ A = a^2 \] ### Step 2: Calculate the new side length after the increase If each side is increased by 10%, the new side length \( a' \) can be calculated as: \[ a' = a + 0.1a = 1.1a \] ### Step 3: Calculate the new area of the square Now, we can find the new area \( A' \) using the new side length: \[ A' = (a')^2 = (1.1a)^2 = 1.21a^2 \] ### Step 4: Determine the increase in area The increase in area can be calculated by subtracting the original area from the new area: \[ \text{Increase in Area} = A' - A = 1.21a^2 - a^2 = 0.21a^2 \] ### Step 5: Calculate the percentage increase in area To find the percentage increase in area, we use the formula: \[ \text{Percentage Increase} = \left(\frac{\text{Increase in Area}}{\text{Original Area}}\right) \times 100 \] Substituting the values we have: \[ \text{Percentage Increase} = \left(\frac{0.21a^2}{a^2}\right) \times 100 = 0.21 \times 100 = 21\% \] ### Conclusion The percentage increase in the area of the square when each side is increased by 10% is **21%**. ---
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