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The circumference of the base of a 16 cm...

The circumference of the base of a 16 cm height solid cone is 33 cm. What is the volume of the cone in `cm^(3)` ?

A

1028

B

616

C

462

D

828

Text Solution

AI Generated Solution

The correct Answer is:
To find the volume of the cone, we can follow these steps: ### Step 1: Find the radius of the base of the cone. The circumference \( C \) of the base of the cone is given by the formula: \[ C = 2\pi r \] We know that \( C = 33 \) cm. Therefore, we can set up the equation: \[ 2\pi r = 33 \] Using \( \pi \approx \frac{22}{7} \), we can substitute this value into the equation: \[ 2 \times \frac{22}{7} \times r = 33 \] ### Step 2: Solve for \( r \). First, simplify the equation: \[ \frac{44}{7} r = 33 \] Now, multiply both sides by \( \frac{7}{44} \) to isolate \( r \): \[ r = 33 \times \frac{7}{44} \] Calculating this gives: \[ r = \frac{231}{44} = \frac{21}{4} \text{ cm} \] ### Step 3: Use the radius to find the volume of the cone. The volume \( V \) of a cone is given by the formula: \[ V = \frac{1}{3} \pi r^2 h \] Substituting \( r = \frac{21}{4} \) cm and \( h = 16 \) cm into the formula: \[ V = \frac{1}{3} \times \frac{22}{7} \times \left(\frac{21}{4}\right)^2 \times 16 \] ### Step 4: Calculate \( r^2 \). First, calculate \( \left(\frac{21}{4}\right)^2 \): \[ \left(\frac{21}{4}\right)^2 = \frac{441}{16} \] ### Step 5: Substitute \( r^2 \) back into the volume formula. Now substitute this back into the volume formula: \[ V = \frac{1}{3} \times \frac{22}{7} \times \frac{441}{16} \times 16 \] The \( 16 \) in the numerator and denominator cancels out: \[ V = \frac{1}{3} \times \frac{22}{7} \times 441 \] ### Step 6: Simplify the expression. Now calculate: \[ V = \frac{22 \times 441}{3 \times 7} \] Calculating \( 3 \times 7 = 21 \): \[ V = \frac{22 \times 441}{21} \] Now divide \( 441 \) by \( 21 \): \[ 441 \div 21 = 21 \] So we have: \[ V = 22 \times 21 = 462 \text{ cm}^3 \] ### Final Answer: The volume of the cone is \( 462 \text{ cm}^3 \). ---
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