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A solid wooden toy is in the shape of a ...

A solid wooden toy is in the shape of a right circular cone mounted on a hemisphere. If the radius of the hemisphere is 4.2 cm and the total height of the toy is 10.2 cm, find the volume of the wooden toy (nearly).

A

`104 cm^(3)`

B

`162 cm^(3)`

C

`427 cm^(3)`

D

`266 cm^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the volume of the solid wooden toy shaped like a right circular cone mounted on a hemisphere, we will follow these steps: ### Step 1: Identify the given values - Radius of the hemisphere (r) = 4.2 cm - Total height of the toy (H) = 10.2 cm ### Step 2: Calculate the height of the cone The height of the cone (h) can be found by subtracting the radius of the hemisphere from the total height of the toy. \[ h = H - r = 10.2 \, \text{cm} - 4.2 \, \text{cm} = 6 \, \text{cm} \] ### Step 3: Calculate the volume of the hemisphere The formula for the volume of a hemisphere is given by: \[ V_{\text{hemisphere}} = \frac{2}{3} \pi r^3 \] Substituting the value of the radius: \[ V_{\text{hemisphere}} = \frac{2}{3} \times \frac{22}{7} \times (4.2)^3 \] Calculating \( (4.2)^3 \): \[ (4.2)^3 = 74.088 \] Now substituting this value back into the volume formula: \[ V_{\text{hemisphere}} = \frac{2}{3} \times \frac{22}{7} \times 74.088 \approx 220.8 \, \text{cm}^3 \] ### Step 4: Calculate the volume of the cone The formula for the volume of a cone is given by: \[ V_{\text{cone}} = \frac{1}{3} \pi r^2 h \] Substituting the values of the radius and height: \[ V_{\text{cone}} = \frac{1}{3} \times \frac{22}{7} \times (4.2)^2 \times 6 \] Calculating \( (4.2)^2 \): \[ (4.2)^2 = 17.64 \] Now substituting this value back into the volume formula: \[ V_{\text{cone}} = \frac{1}{3} \times \frac{22}{7} \times 17.64 \times 6 \] Calculating: \[ V_{\text{cone}} \approx \frac{1}{3} \times \frac{22}{7} \times 105.84 \approx 79.2 \, \text{cm}^3 \] ### Step 5: Calculate the total volume of the wooden toy Now, we can find the total volume of the wooden toy by adding the volumes of the hemisphere and the cone: \[ V_{\text{total}} = V_{\text{hemisphere}} + V_{\text{cone}} \approx 220.8 \, \text{cm}^3 + 79.2 \, \text{cm}^3 = 300 \, \text{cm}^3 \] ### Final Answer The volume of the wooden toy is approximately \( 300 \, \text{cm}^3 \). ---
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