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The ratio of the volume of a cube and a solid sphere is 363 : 49. The ratio of an edge of the cube and the radius of the sphere is (taking `pi = (22)/(7)`)

A

`7:11`

B

`22:7`

C

`11:7`

D

`7:22`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the edge of the cube (A) to the radius of the sphere (R) given the ratio of their volumes. ### Step-by-Step Solution: 1. **Understand the Volume Formulas**: - The volume of a cube (V_cube) is given by: \[ V_{\text{cube}} = A^3 \] - The volume of a sphere (V_sphere) is given by: \[ V_{\text{sphere}} = \frac{4}{3} \pi R^3 \] 2. **Set Up the Ratio**: - We know from the problem that: \[ \frac{V_{\text{cube}}}{V_{\text{sphere}}} = \frac{363}{49} \] - Substituting the volume formulas, we have: \[ \frac{A^3}{\frac{4}{3} \pi R^3} = \frac{363}{49} \] 3. **Cross-Multiply to Simplify**: - Cross-multiplying gives: \[ A^3 \cdot 49 = \frac{4}{3} \pi R^3 \cdot 363 \] - Rearranging this, we get: \[ A^3 = \frac{4 \cdot 363}{3 \cdot 49} \cdot \pi R^3 \] 4. **Substituting the Value of π**: - Given that \(\pi = \frac{22}{7}\), we substitute this into our equation: \[ A^3 = \frac{4 \cdot 363}{3 \cdot 49} \cdot \frac{22}{7} R^3 \] 5. **Calculate the Right Side**: - First calculate \(\frac{4 \cdot 363 \cdot 22}{3 \cdot 49 \cdot 7}\): - Calculate \(4 \cdot 363 = 1452\) - Calculate \(3 \cdot 49 = 147\) - Now, substitute: \[ A^3 = \frac{1452 \cdot 22}{147 \cdot 7} R^3 \] 6. **Simplifying the Ratio**: - Now we can simplify: \[ A^3 = \frac{31944}{1029} R^3 \] - To find the ratio \( \frac{A^3}{R^3} \): \[ \frac{A^3}{R^3} = \frac{31944}{1029} \] 7. **Taking the Cube Root**: - Taking the cube root of both sides gives us: \[ \frac{A}{R} = \sqrt[3]{\frac{31944}{1029}} \] 8. **Finding the Ratio**: - After simplifying, we find: \[ \frac{A}{R} = \frac{11}{\frac{22}{7}} = \frac{11 \cdot 7}{22} = \frac{77}{22} = \frac{7}{2} \] 9. **Final Answer**: - Therefore, the ratio of the edge of the cube to the radius of the sphere is: \[ \frac{A}{R} = \frac{11}{7} \]
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