Some bricks are arranged in an area measuring 20 cu. M. If the length, breadth and height of each brick is 25 cm 12.5 cm and 8 cm respectively, then in the pile the number of bricks are (suppose there is no gap in between two bricks)

Options

A. a) 6000
B. b) 8000
C. c) 4000
D. d) 10000

Answer

To find the number of bricks that can be arranged in a volume of 20 cubic meters, we will follow these steps:

### Step 1: Calculate the volume of one brick.
The volume \( V \) of a brick can be calculated using the formula:
\[ V = \text{length} \times \text{breadth} \times \text{height} \]
Given:
- Length = 25 cm
- Breadth = 12.5 cm
- Height = 8 cm

Substituting the values:
\[ V = 25 \, \text{cm} \times 12.5 \, \text{cm} \times 8 \, \text{cm} \]

### Step 2: Perform the multiplication.
Calculating the volume:
\[ V = 25 \times 12.5 = 312.5 \, \text{cm}^2 \]
Now, multiply by the height:
\[ V = 312.5 \, \text{cm}^2 \times 8 \, \text{cm} = 2500 \, \text{cm}^3 \]

### Step 3: Convert the total volume from cubic meters to cubic centimeters.
Since \( 1 \, \text{m}^3 = 10^6 \, \text{cm}^3 \), we convert 20 m³:
\[ 20 \, \text{m}^3 = 20 \times 10^6 \, \text{cm}^3 = 20000000 \, \text{cm}^3 \]

### Step 4: Calculate the number of bricks.
To find the number of bricks \( N \), we divide the total volume by the volume of one brick:
\[ N = \frac{\text{Total Volume}}{\text{Volume of one brick}} = \frac{20000000 \, \text{cm}^3}{2500 \, \text{cm}^3} \]

### Step 5: Perform the division.
Calculating the number of bricks:
\[ N = \frac{20000000}{2500} = 8000 \]

### Final Answer:
The number of bricks that can be arranged in the pile is **8000**.

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